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Provide a from_json overload for std::map

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This overload is chosen only when BasicJsonType::string_t
is not constructible from std::map::key_type.

Currently, converting a map to json treats it as an array of pairs.

fixes #1079
This commit is contained in:
Théo DELRIEU 2018-05-14 11:51:37 +02:00
parent 567fe9b7a0
commit c5e63fd684
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GPG key ID: A5A505438C20539A
3 changed files with 61 additions and 0 deletions
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20
include/nlohmann/detail/conversions/from_json.hpp
View file

@ -5,6 +5,7 @@
#include <ciso646> // and, not
#include <forward_list> // forward_list
#include <iterator> // inserter, front_inserter, end
#include <map> // map
#include <string> // string
#include <tuple> // tuple, make_tuple
#include <type_traits> // is_arithmetic, is_same, is_enum, underlying_type, is_convertible
@ -277,6 +278,25 @@ void from_json(const BasicJsonType& j, std::tuple<Args...>& t)
from_json_tuple_impl(j, t, index_sequence_for<Args...> {});
}
template <typename BasicJsonType, typename Key, typename Value,
typename = enable_if_t<not std::is_constructible<
typename BasicJsonType::string_t, Key>::value>>
void from_json(const BasicJsonType& j, std::map<Key, Value>& m)
{
if (JSON_UNLIKELY(not j.is_array()))
{
JSON_THROW(type_error::create(302, "type must be array, but is " + std::string(j.type_name())));
}
for (const auto& p : j)
{
if (JSON_UNLIKELY(not p.is_array()))
{
JSON_THROW(type_error::create(302, "type must be array, but is " + std::string(p.type_name())));
}
m.emplace(p.at(0).template get<Key>(), p.at(1).template get<Value>());
}
}
struct from_json_fn
{
private: