Fixed modular reduction bug in the special field for P-256 (in some rare cases, value would end up being negative, which would corrupt subsequent operations).
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d8641065c9
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2b738493bd
3 changed files with 98 additions and 4 deletions
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@ -1122,6 +1122,22 @@ mul_f256(uint32_t *d, const uint32_t *a, const uint32_t *b)
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t[14] -= cc << 10;
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t[7] -= cc << 5;
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t[0] += cc;
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/*
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* If the carry is negative, then after carry propagation, we may
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* end up with a value which is negative, and we don't want that.
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* Thus, in that case, we add the modulus. Note that the subtraction
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* result, when the carry is negative, is always smaller than the
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* modulus, so the extra addition will not make the value exceed
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* twice the modulus.
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*/
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cc >>= 31;
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t[0] -= cc;
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t[7] += cc << 5;
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t[14] += cc << 10;
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t[17] -= cc << 3;
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t[19] += cc << 9;
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norm13(d, t, 20);
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}
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@ -1195,6 +1211,22 @@ square_f256(uint32_t *d, const uint32_t *a)
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t[14] -= cc << 10;
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t[7] -= cc << 5;
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t[0] += cc;
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/*
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* If the carry is negative, then after carry propagation, we may
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* end up with a value which is negative, and we don't want that.
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* Thus, in that case, we add the modulus. Note that the subtraction
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* result, when the carry is negative, is always smaller than the
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* modulus, so the extra addition will not make the value exceed
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* twice the modulus.
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*/
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cc >>= 31;
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t[0] -= cc;
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t[7] += cc << 5;
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t[14] += cc << 10;
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t[17] -= cc << 3;
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t[19] += cc << 9;
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norm13(d, t, 20);
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}
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@ -394,7 +394,7 @@ mul_f256(uint32_t *d, const uint32_t *a, const uint32_t *b)
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uint32_t t[18];
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uint64_t s[18];
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uint64_t cc, x;
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uint32_t z;
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uint32_t z, c;
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int i;
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mul9(t, a, b);
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@ -465,7 +465,15 @@ mul_f256(uint32_t *d, const uint32_t *a, const uint32_t *b)
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d[8] &= 0xFFFF;
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/*
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* Subtract cc*p.
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* One extra round of reduction, for cc*2^256, which means
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* adding cc*(2^224-2^192-2^96+1) to a 256-bit (nonnegative)
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* value. If cc is negative, then it may happen (rarely, but
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* not neglectibly so) that the result would be negative. In
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* order to avoid that, if cc is negative, then we add the
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* modulus once. Note that if cc is negative, then propagating
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* that carry must yield a value lower than the modulus, so
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* adding the modulus once will keep the final result under
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* twice the modulus.
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*/
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z = (uint32_t)cc;
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d[3] -= z << 6;
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@ -473,6 +481,12 @@ mul_f256(uint32_t *d, const uint32_t *a, const uint32_t *b)
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d[7] -= ARSH(z, 18);
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d[7] += (z << 14) & 0x3FFFFFFF;
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d[8] += ARSH(z, 16);
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c = z >> 31;
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d[0] -= c;
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d[3] += c << 6;
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d[6] += c << 12;
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d[7] -= c << 14;
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d[8] += c << 16;
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for (i = 0; i < 9; i ++) {
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uint32_t w;
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@ -492,7 +506,7 @@ square_f256(uint32_t *d, const uint32_t *a)
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uint32_t t[18];
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uint64_t s[18];
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uint64_t cc, x;
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uint32_t z;
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uint32_t z, c;
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int i;
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square9(t, a);
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@ -563,7 +577,15 @@ square_f256(uint32_t *d, const uint32_t *a)
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d[8] &= 0xFFFF;
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/*
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* Subtract cc*p.
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* One extra round of reduction, for cc*2^256, which means
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* adding cc*(2^224-2^192-2^96+1) to a 256-bit (nonnegative)
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* value. If cc is negative, then it may happen (rarely, but
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* not neglectibly so) that the result would be negative. In
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* order to avoid that, if cc is negative, then we add the
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* modulus once. Note that if cc is negative, then propagating
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* that carry must yield a value lower than the modulus, so
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* adding the modulus once will keep the final result under
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* twice the modulus.
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*/
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z = (uint32_t)cc;
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d[3] -= z << 6;
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@ -571,6 +593,12 @@ square_f256(uint32_t *d, const uint32_t *a)
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d[7] -= ARSH(z, 18);
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d[7] += (z << 14) & 0x3FFFFFFF;
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d[8] += ARSH(z, 16);
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c = z >> 31;
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d[0] -= c;
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d[3] += c << 6;
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d[6] += c << 12;
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d[7] -= c << 14;
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d[8] += c << 16;
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for (i = 0; i < 9; i ++) {
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uint32_t w;
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